14r^2-350=0

Solution for 14r^2-350=0 equation:

14r^2-350=0

a = 14; b = 0; c = -350;
Δ = b2-4ac
Δ = 02-4·14·(-350)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-140}{2*14}=\frac{-140}{28}
=-5
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+140}{2*14}=\frac{140}{28}
=5
$